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  1. terryZ_

    I wonder if the "7" in your name represents the decades you're going to staff Manacube for? It...

    I wonder if the "7" in your name represents the decades you're going to staff Manacube for? It better be
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  2. terryZ_

    Equation 1 (E1) = 3x + 2y = 7 Equation 2 (E2) = x - y = 1 E2 * 2 = 2x - 2y = 2...

    Equation 1 (E1) = 3x + 2y = 7 Equation 2 (E2) = x - y = 1 E2 * 2 = 2x - 2y = 2 Add LHS and RHS of E1 and E2 * 2 3x + 2x + 2y - 2y = 7 + 2 5x = 9 x = 9/5 Put back into E2 9/5 - y = 1 9/5 - 1 = y 9/5 - 5/5 = y y = 4/5 Therefore, x = 9/5, y = 4/5
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  3. terryZ_

    2^(3t) is the same as 2^(3)^(t), which is 8^(t) Therefore your equation would give 8^(t) = 8^(t...

    2^(3t) is the same as 2^(3)^(t), which is 8^(t) Therefore your equation would give 8^(t) = 8^(t + 1) t = t + 1 Either no solution, or typo in question
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  4. terryZ_

    L'Hopital's rule lim(x->0) f(x)/g(x) = lim(x->0) f'(x)/g'(x) therefore lim(x -> 0) [sin(x) / x]...

    L'Hopital's rule lim(x->0) f(x)/g(x) = lim(x->0) f'(x)/g'(x) therefore lim(x -> 0) [sin(x) / x] = lim(x -> 0) [cos(x) / 1] = cos(0) / 1 = 1
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  5. terryZ_

    I always thought that "cute" started with "c", but now i know it starts with "u"

    I always thought that "cute" started with "c", but now i know it starts with "u"
  6. terryZ_

    Cartesian form or polar form?

    Cartesian form or polar form?
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  7. terryZ_

    f'(x) = 8x^3 + 9x^2 - 8x + 5

    f'(x) = 8x^3 + 9x^2 - 8x + 5
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  8. terryZ_

    This is just sec^2(x) Use trig identities: sin^2(x) + cos^2(x) = 1 therefore sin^2(x) + cos^2(x)...

    This is just sec^2(x) Use trig identities: sin^2(x) + cos^2(x) = 1 therefore sin^2(x) + cos^2(x) + tan^2(x) = 1 + tan^2(x) 1 + tan^2(x) = sec^2(x)
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  9. terryZ_

    If nothing lasts forever, can you be my nothing?

    If nothing lasts forever, can you be my nothing?
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  10. terryZ_

    Jacob's answer is incorrect - the coefficient for x^4 should be 1/2, not 1/4 since ∫2x^3dx...

    Jacob's answer is incorrect - the coefficient for x^4 should be 1/2, not 1/4 since ∫2x^3dx should be (2/4)x^4 = (1/2)x^4
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  11. terryZ_

    News Post Bedrock Support

    Let's go, bedrock support! We can play Manacube on the toilet now? Who's to say we haven't done so already :cool:
  12. terryZ_

    [Factions Beta] Raid Mobs make walls and cannons completely obsolete

    Hey, thank you for the feedback on raid mobs. Just a quick disclaimer before I respond; these are just all my personal thoughts and I don't speak for any other staff, Dacon etc - so my word isn't official on what will be changed, but just suggestions and thoughts. Currently, Factions is still...