VenomousLemon
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  • Day 15 of commenting complex math but it gets harder each day

    Evaluate the double integral:
    ∬(2xy + 3) dA, where the region R is bounded by x = 0, x = 1, y = 0, and y = 2.
    Day 12 of commenting complex math but it gets harder each day

    Determine the eigenvalues and eigenvectors of the matrix:
    | 4 -1 |
    | |
    | 2 3 |
    Isn't math so fun... Like a puzzle, right? Don't you like puzzles? Mrs Venemous Lememous Man.. I've heard you love puzzles, especially ones about a myth called The Braincell Man. ;D
    Day 11 of commenting complex math but it gets harder each day

    Solve the system of equations:
    3x + 2y = 7
    x - y = 1
    terryZ_
    terryZ_
    Equation 1 (E1) = 3x + 2y = 7
    Equation 2 (E2) = x - y = 1
    E2 * 2 = 2x - 2y = 2
    Add LHS and RHS of E1 and E2 * 2
    3x + 2x + 2y - 2y = 7 + 2
    5x = 9
    x = 9/5
    Put back into E2
    9/5 - y = 1
    9/5 - 1 = y
    9/5 - 5/5 = y
    y = 4/5
    Therefore, x = 9/5, y = 4/5
    Day 10 of commenting complex math but it gets harder each day (ggs, I haven't forgotten yet...)

    Find the value of t that satisfies the equation:
    2^(3t) = 8^(t + 1)
    VenomousLemon
    VenomousLemon
    Congrats you made it to day 10 have a cookie
    ItzMarni
    ItzMarni
    Ikr, I haven't forgotten... yet-
    terryZ_
    terryZ_
    2^(3t) is the same as 2^(3)^(t), which is 8^(t)
    Therefore your equation would give 8^(t) = 8^(t + 1)
    t = t + 1
    Either no solution, or typo in question
    Day 9 of commenting complex math but it gets harder each day

    Evaluate the following limit:
    lim(x -> 0) [sin(x) / x]
    terryZ_
    terryZ_
    L'Hopital's rule
    lim(x->0) f(x)/g(x) = lim(x->0) f'(x)/g'(x)
    therefore lim(x -> 0) [sin(x) / x]
    = lim(x -> 0) [cos(x) / 1]
    = cos(0) / 1
    = 1
    Day 8 of commenting complex math but it gets harder each day

    Simplify the logarithmic expression:
    log(base 3)(27) + log(base 2)(8) - log(base 4)(2)
    Day 7 of commenting complex math but it gets harder each day

    Solve for z:
    3z + 5i = 2 - (z - 1)i
    terryZ_
    terryZ_
    Cartesian form or polar form?
    ItzMarni
    ItzMarni
    Idk, the answer is: The solution to the equation is z = 1/2 - i.
    Day 6 of commenting complex math but it gets harder each day

    Find the derivative of the function with respect to x:
    f(x) = 2x^4 + 3x^3 - 4x^2 + 5x - 1
    Day 5 of commenting complex math but it gets harder each day

    Simplify the following trigonometric expression:
    sin^2(x) + cos^2(x) + tan^2(x)
    terryZ_
    terryZ_
    This is just sec^2(x)
    Use trig identities:
    sin^2(x) + cos^2(x) = 1
    therefore sin^2(x) + cos^2(x) + tan^2(x) = 1 + tan^2(x)
    1 + tan^2(x) = sec^2(x)
    Day 3 of commenting complex math but it gets harder each day

    Evaluate the integral:
    ∫(2x^3 + 5x^2 - 3x + 7) dx
    EvanTech
    EvanTech
    terryZ_
    terryZ_
    Jacob's answer is incorrect - the coefficient for x^4 should be 1/2, not 1/4

    since ∫2x^3dx should be (2/4)x^4
    = (1/2)x^4
    TeamJacob
    TeamJacob
    You are right. ig I made a small booboo on my math
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